30x^2+450x=1350

Solution for 30x^2+450x=1350 equation:

30x^2+450x=1350

We move all terms to the left:

30x^2+450x-(1350)=0

a = 30; b = 450; c = -1350;
Δ = b2-4ac
Δ = 4502-4·30·(-1350)
Δ = 364500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{364500}=\sqrt{72900*5}=\sqrt{72900}*\sqrt{5}=270\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(450)-270\sqrt{5}}{2*30}=\frac{-450-270\sqrt{5}}{60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(450)+270\sqrt{5}}{2*30}=\frac{-450+270\sqrt{5}}{60}
$